$$(x+y+z)^2$$

How to find the sum of three square numbers

Earlier we saw how to solve the differnce of two whole squares. Now we will see how to find the difference of two seperate square numbers.

THE FORMULA IS: $$x^2 - y^2 = (x+y)*(x-y)$$

Let us work it out with an example:-

let x=7 and y=5

$$x^2 - y^2 = (x+y)*(x-y)$$

$$7^2 - 5^2 = (7+5)*(7-5)$$

12*2

24